1.求下列直线方程：

高中代数题直线的方程是:y=[(1+3

y=(1+3p^2)x/(1-3p^2)+p^3-(p+3p^3)/(1-3p^2) y=x^3 x^3=(1+3p^2)x/(1-3p^2)+p^3-(p+3p^3)/(1-3p^2) (3p^2-1)x^3+(3p^2+1)x-p(3p^4+2p^2+1)=0 (x-p)[(3p^2-1)x^2+p(3p^2-1)x+3p^4+2p^2+1]=0 x-p=0 x=p (3p^2-1)x^2+p(3p^2-1)x+3p^4+2p^2+1=0 有两个不同的根：3p^2-1不为0 p^2不为1/3 且DEL>0 p^2*(3p^2-1)^2-4(3p^2-1)(3p^4+2p^...全部

  y=(1+3p^2)x/(1-3p^2)+p^3-(p+3p^3)/(1-3p^2) y=x^3 x^3=(1+3p^2)x/(1-3p^2)+p^3-(p+3p^3)/(1-3p^2) (3p^2-1)x^3+(3p^2+1)x-p(3p^4+2p^2+1)=0 (x-p)[(3p^2-1)x^2+p(3p^2-1)x+3p^4+2p^2+1]=0 x-p=0 x=p (3p^2-1)x^2+p(3p^2-1)x+3p^4+2p^2+1=0 有两个不同的根：3p^2-1不为0 p^2不为1/3 且DEL>0 p^2*(3p^2-1)^2-4(3p^2-1)(3p^4+2p^2+1)>0 3p^2-1<0 -√3/3  收起