不等式的问题
若不等式ax^2+2x+b>0的解集是｛x│-1/30
因为:不等式ax^2+2x+b>0的解集是｛x│-1/30可分解为(x+1/3)(x-1/2)x^2-1/6x-1/6-6x^2+x+1>0 ==>-12x^2+2x+2>0 ==>a=-12 b=2
(1) bx^2+2x-a>0
bx^2+2x-a>0 ==>2x^2+2x+12>0 ==>(x+1/2)^2+23/4>0
不等式bx^2+2x-a>0的解集是｛x│-000
bx^2+2x+a>0 ==>2x^2+2x-12>0 ==>(x-2)(x+3)>0 ==>x2
不等式bx^2+2x+a>0的解集是｛x│x2x^2+2...全部
若不等式ax^2+2x+b>0的解集是｛x│-1/30
因为:不等式ax^2+2x+b>0的解集是｛x│-1/30可分解为(x+1/3)(x-1/2)x^2-1/6x-1/6-6x^2+x+1>0 ==>-12x^2+2x+2>0 ==>a=-12 b=2
(1) bx^2+2x-a>0
bx^2+2x-a>0 ==>2x^2+2x+12>0 ==>(x+1/2)^2+23/4>0
不等式bx^2+2x-a>0的解集是｛x│-000
bx^2+2x+a>0 ==>2x^2+2x-12>0 ==>(x-2)(x+3)>0 ==>x2
不等式bx^2+2x+a>0的解集是｛x│x2x^2+2x-12(x-2)(x+3)-30
-bx^2+2x-a>0 ==>-2x^2+2x+12>0 ==>(x+2)(x-3)-20的解集是｛x│-2 收起
