1×2 分之1 加2×3 分之1 加3×4 分之1 加

求解矩阵方程AX=B

解: (A,B) = 2 1 -3 1 -1 1 2 2 2 0-1 3 2 -2 5r1-2r2, r3 r2 0 -3 -7 -3 -1 1 2 2 2 0 0 5 4 0 5r3 2r1 0 -3 -7 -3 -1 1 2 2 2 0 0 -1 -10 -6 3r1-3r3, r2 2r3 0 0 23 15 -10 1 0 -18 -10 6 0 -1 -10 -6 3r1*(1/23), r3*(-1) 0 0 1 15/23 -10/23 1 0 -18 -10 6 0 1 10 6 -3r2...全部

  解: (A,B) = 2 1 -3 1 -1 1 2 2 2 0-1 3 2 -2 5r1-2r2, r3 r2 0 -3 -7 -3 -1 1 2 2 2 0 0 5 4 0 5r3 2r1 0 -3 -7 -3 -1 1 2 2 2 0 0 -1 -10 -6 3r1-3r3, r2 2r3 0 0 23 15 -10 1 0 -18 -10 6 0 -1 -10 -6 3r1*(1/23), r3*(-1) 0 0 1 15/23 -10/23 1 0 -18 -10 6 0 1 10 6 -3r2 18r1,r3-10r1 0 0 1 15/23 -10/23 1 0 0 40/23 -42/23 0 1 0 -12/23 31/23交换行得 1 0 0 40/23 -42/23 0 1 0 -12/23 31/23 0 0 1 15/23 -10/23所以 B = 40/23 -42/23-12/23 31/23 15/23 -10/23。
  满意请采纳^_^。收起