数学公式求推导、函数的和差积商的导数公式推导、只求商和积公式推导、在线等、
(uv)'=lim(h→0)[u(x h)v(x h)-uv]/h=lim(h→0)[u(x h)v(x h) u(x h)v-u(x h)v-uv]/h=lim(h→0)[u(x h)]×[v(x h)-v(x)]/h lim(h→0)[v(x)]×[u(x h)-u(x)]/h=u(x)v'(x) u'(x)v(x)=u'v uv'(u/v)'=[u*v^(-1)]'=u'*[v^(-1)] [v^(-1)]'*u=u'*[v^(-1)] (-1)v^(-2)*v'*u=u'/v - u*v'/v²通分得(u/v)=(u'v-uv')/v²累死我了,请加分!。 全部
(uv)'=lim(h→0)[u(x h)v(x h)-uv]/h=lim(h→0)[u(x h)v(x h) u(x h)v-u(x h)v-uv]/h=lim(h→0)[u(x h)]×[v(x h)-v(x)]/h lim(h→0)[v(x)]×[u(x h)-u(x)]/h=u(x)v'(x) u'(x)v(x)=u'v uv'(u/v)'=[u*v^(-1)]'=u'*[v^(-1)] [v^(-1)]'*u=u'*[v^(-1)] (-1)v^(-2)*v'*u=u'/v - u*v'/v²通分得(u/v)=(u'v-uv')/v²累死我了,请加分!。
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