帮我解道题x-4分之1+x-1分
1/(x-4)+4/(x-1)=2/(x-3)+3/(x-2)移项得:
1/(x-4)-3/(x-2)=2/(x-3)-4/(x-1)
1/(x-4)-3/(x-2)=[(x-2)-3(x-4)]/[(x-2)(x-4)]=(-2x+10)/(x^2-6x+8)
2/(x-3)-4/(x-1)=[2(x-1)-4(x-3)]/[(x-1)(x-3)]=(-2x+10)/(x^2-4x+3)
∴(-2x+10)/(x^2-6x+8)=(-2x+10)/(x^2-4x+3)
①当-2x+10=0时解得:x1=5
②当-2x+10≠0时有:
x^2-6x+8=x^2-4x+3
解得:x2=5/2...全部
1/(x-4)+4/(x-1)=2/(x-3)+3/(x-2)移项得:
1/(x-4)-3/(x-2)=2/(x-3)-4/(x-1)
1/(x-4)-3/(x-2)=[(x-2)-3(x-4)]/[(x-2)(x-4)]=(-2x+10)/(x^2-6x+8)
2/(x-3)-4/(x-1)=[2(x-1)-4(x-3)]/[(x-1)(x-3)]=(-2x+10)/(x^2-4x+3)
∴(-2x+10)/(x^2-6x+8)=(-2x+10)/(x^2-4x+3)
①当-2x+10=0时解得:x1=5
②当-2x+10≠0时有:
x^2-6x+8=x^2-4x+3
解得:x2=5/2
经检验x1=5,x2=5/2都是原方程的解
∴原分式方程的解是x1=5,x2=5/2.。
收起