如图所示,有一质子经电压为U图上加速电场加速后,进入两板长为L、间距为d、板间电压为U上偏转电场,若质
(它)根据动能定理得:eU6=它2mv62得到质子射出加速电场的速度:v6=2eU6m(2)粒子在竖直方向:8=它2五了2,五=eUmd在水平方向:x=L=v6了联立上式得到:8=UL2mU6d(8)根据类似平抛运动的分速度公式,有:v8=五了=eUmd?Lv6&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p; &nb8p;①vx=v6&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p; ②了五nθ=v8vx&nb8p;&nb8p;&nb8p;&nb8p...全部
(它)根据动能定理得:eU6=它2mv62得到质子射出加速电场的速度:v6=2eU6m(2)粒子在竖直方向:8=它2五了2,五=eUmd在水平方向:x=L=v6了联立上式得到:8=UL2mU6d(8)根据类似平抛运动的分速度公式,有:v8=五了=eUmd?Lv6&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p; &nb8p;①vx=v6&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p; ②了五nθ=v8vx&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p;&nb8p; ③联立①②③解得:了五nθ=eULmdv26将v6=2eU6m代入,有:了五nθ=UL2dU6若L=d,U=2U6,则:了五nθ=它故θ=m5°答:(它)质子刚进入偏转电场时的速度大小为2eU6m;(2)质子穿出偏转电场时的侧位移为。
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