化简（1 2的1/32次方）（1 2的1/16次方）（1 2的1/8次） ,结果是( )
原式=(1 2^(1/32))(1 2^(1/16))(1 2^(1/8))(1 2^(1/4))(1 2^(1/2))=[(1 2^(1/32))(1 2^(1/16))(1 2^(1/8))(1 2^(1/4))(1 2^(1/2))*((1-2^(1/32))]/(1-2^(1/32))=[(1-2^(1/16))(1 2^(1/16))(1 2^(1/8))(1 2^(1/4))(1 2^(1/2))]/(1-2^(1/32))=[(1-2^(1/8))(1 2^(1/8))(1 2^(1/4))(1 2^(1/2))]/(1-2^(1/32))=[(1-2^(1/4))(1 2^...全部
原式=(1 2^(1/32))(1 2^(1/16))(1 2^(1/8))(1 2^(1/4))(1 2^(1/2))=[(1 2^(1/32))(1 2^(1/16))(1 2^(1/8))(1 2^(1/4))(1 2^(1/2))*((1-2^(1/32))]/(1-2^(1/32))=[(1-2^(1/16))(1 2^(1/16))(1 2^(1/8))(1 2^(1/4))(1 2^(1/2))]/(1-2^(1/32))=[(1-2^(1/8))(1 2^(1/8))(1 2^(1/4))(1 2^(1/2))]/(1-2^(1/32))=[(1-2^(1/4))(1 2^(1/4))(1 2^(1/2))]/(1-2^(1/32))=[(1-2^(1/2))(1 2^(1/2))]/(1-2^(1/32))=(1-2)/(1-2^(1/32))=-1/(1-2^(1/32))。
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