解方程:(3分之2x-)-(12
(3分之2x-)-(12分之10x+1)=(4分之2x+1)-1
(2x/3)+(10x+1)/12=[(2x+1)/4]-1
(2x/3)+(10x/12)+(1/12)=(2x/4)+(1/4)-1
(2x/3)+(10x/12)-(2x/4)=(1/4)-1-(1/12)
通分
(8x/12)+(10x/12)-(6x/12)=(3/12)-(12/12)-(1/12)
(8x+10x-6x)/12=(3-12-1)/12
12x/12=-10/12
x=-5/6。
(3分之2x-)-(12分之10x+1)=(4分之2x+1)-1
(2x/3)+(10x+1)/12=[(2x+1)/4]-1
(2x/3)+(10x/12)+(1/12)=(2x/4)+(1/4)-1
(2x/3)+(10x/12)-(2x/4)=(1/4)-1-(1/12)
通分
(8x/12)+(10x/12)-(6x/12)=(3/12)-(12/12)-(1/12)
(8x+10x-6x)/12=(3-12-1)/12
12x/12=-10/12
x=-5/6。
收起