求几个简单c语言程序设计判断任意
1 判断闰年
void main()
{
int year;
printf("please input a year: ");
scanf("%d",&year);
if((year%4==0&&year%100!=0)||(year%400==0))
printf("The year: %d is RunNian!\n",year);
else
printf("The year: %d isn't RunNian!\n",year);
}
2 输出图形
void main()
{
int i,j;
for(i=0;i
void main()
{
long num;
int n[7],pl...全部
1 判断闰年
void main()
{
int year;
printf("please input a year: ");
scanf("%d",&year);
if((year%4==0&&year%100!=0)||(year%400==0))
printf("The year: %d is RunNian!\n",year);
else
printf("The year: %d isn't RunNian!\n",year);
}
2 输出图形
void main()
{
int i,j;
for(i=0;i
void main()
{
long num;
int n[7],place,i,flag;
printf("请输入一个整数（0 ~ 999999）:");
scanf("%ld",&num);
if(num>99999)
place=6;
else if(num>9999)
place=5;
else if(num>999)
place=4;
else if(num>99)
place=3;
else if(num>9)
place=2
else place=1;
printf("位数:%d\n",place);
n[6]=mun/10000
n[5]=num/10000;
n[4]=(int)(num-n[5]*10000)/1000;
n[3]=(int)(num-n[5]*10000-n[4]*1000)/100;
n[2]=(int)(num-n[5]*10000-n[4]*1000-n[3]*100)/10;
n[1]=(int)(num-n[5]*10000-n[4]*1000-n[3]*100-n[2]*10);
printf("反序数字为：");
5 连接字符串
char str1[100];
char str2[100];
void Strcat(str1,str2)
char *str1,*str2;
{
int len;
int i=0;
len=strlen(str1);
while(*(str2+i))
{
*(str1+i+len)=*(str2+i);
i++;
}
}
int main()
{
scanf("%s",&str1);
scanf("%s",&str2);
Strcat(&str1,&str2);
printf("%s",str1);
getchar();
getchar();
}
6 判断素数
void main()
{ int m,i,k;
printf("please input a number:\n");
scanf("%d",&m);
k=sqrt(m);
for(i=2;i=k)
printf("该数是素数");
else
printf("该数不是素数");
}
另外一个慢慢考虑中……。
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