因式分解(a^4)b+(a^3)b^2-(a^2)b^3-a(b^4)
8x^3+4x^2-2x-1
x^3-2x^2-x+2+x^5-2x^4
解答:
(a^4)b+(a^3)b^2-(a^2)b^3-a(b^4)
=ab(a^3+a^2b-ab^2-b^3)
=ab[a^2(a+b)-b^(a+b)]
=ab(a+b)(a^2-b^2)
=ab(a+b)^2(a-b)
8x^3+4x^2-2x-1
=4x^2(2x+1)-(2x+1)
=(2x+1)(4x^2-1)
=(2x-1)(2x+1)^2
x^3-2x^2-x+2+x^5-2x^4
=(x^5-2x^4)+(x^3-2x^2)-(x-2)
=x^4(x-2)+x^2(x-2)-(x-2)
=(x-2)(x^4+x^2-1)
=(x-2)(x^2-1-√5/2)(x^2-...全部
解答:
(a^4)b+(a^3)b^2-(a^2)b^3-a(b^4)
=ab(a^3+a^2b-ab^2-b^3)
=ab[a^2(a+b)-b^(a+b)]
=ab(a+b)(a^2-b^2)
=ab(a+b)^2(a-b)
8x^3+4x^2-2x-1
=4x^2(2x+1)-(2x+1)
=(2x+1)(4x^2-1)
=(2x-1)(2x+1)^2
x^3-2x^2-x+2+x^5-2x^4
=(x^5-2x^4)+(x^3-2x^2)-(x-2)
=x^4(x-2)+x^2(x-2)-(x-2)
=(x-2)(x^4+x^2-1)
=(x-2)(x^2-1-√5/2)(x^2-1+√5/2)
=(x-2)(x^2-1-√5/2)(x^2-1+√5/2)
=(x-2)[x+√(1+√5/2][x-√(1+√5/2)](x^2-1+√5/2)。
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