请解初一数学
=[1/(-1/4)^2]-(-1)^2006+(2/3)^11×(-3/2)^12
=[1/(1/16)]-1+(2/3)^11×(3/2)^12
=16-1+(2/3)^11×(3/2)^11×(3/2)
=15+[(2/3)×(3/2)]^11×(3/2)
=15+1^11×(3/2)
=15+(3/2)
=33/2。
=[1/(-1/4)^2]-(-1)^2006+(2/3)^11×(-3/2)^12
=[1/(1/16)]-1+(2/3)^11×(3/2)^12
=16-1+(2/3)^11×(3/2)^11×(3/2)
=15+[(2/3)×(3/2)]^11×(3/2)
=15+1^11×(3/2)
=15+(3/2)
=33/2。
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