(1+a+a^2/4)/(a+2) (2-32a^4)/(4a^2+1)/(2a+1) 分解下,谢谢了
1)(1+a+a^2/4)/(a+2)
=(1/4)(4+4a+a^2)/(a+2)
=(1/4)(a+2)^2/(a+2)
=(a+1)/4
=1/4+a/4
2)(2-32a^4)/(4a^2+1)/(2a+1)
=-2(16a^4-1)/[(4a^2+1)(2a+1)]
=-2(4a^2-1)(4a^2+1)/[(4a^2+1)(2a^2+1)]
=-2(2a-1)(2a+1)/(2a+1)
=-2(2a-1)。
。
(1+a+a^2/4)/(a+2)
=[(1/4)(a^2+4a+4)]/(a+2)
=[(1/4)(a+2)^2]/(a+2)
=(1/4)(a+2)
(2-32a^4)/(4a^2+1)/(2a+1)
=2[1-(4a^2)^2]/(4a^2+1)/(2a+1)
=2(1+4a^2)(1-4a^2)/(4a^2+1)/(2a+1)
=2(1-4a^2)/(2a+1)
=2(1-2a)(1+2a)/(2a+1)
=2(1-2a)
。